# Pythagoras formula

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In the figure below, AOB is a circular sector of 90° degrees. C is a point on arc AB, ACDE and CBFG are squares. Prove that OD^2 + OG^2 = 3.AB^2. (For C = B the formula is Pythagoras' theorem for the right triangle ODH) http://gogeometry.com/school-college/1/p1022-circular-sector-90-degrees-squares-metric-relations-online-math.htm

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Great idea for applications of Pythagoras' theorem - finding the shortest distance between two points. Could easily be adapted to your area using a screengrab from Google maps.

In the figure below, AOB is a circular sector of 90° degrees. C is a point on arc AB, ACDE and CBFG are squares. Prove that OD^2 + OG^2 = 3.AB^2. (For C = B the formula is Pythagoras' theorem for the right triangle ODH) http://gogeometry.com/school-college/1/p1022-circular-sector-90-degrees-squares-metric-relations-online-math.htm

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